How many moles and numbers of ions of each type are present in the following aqueous solutions?

(a) 2.8 mL of 2.41 M magnesium chloride


(b) 380. mL of a solution containing 3.65 g/L aluminum sulfate


(c)2.54 L of a solution containing 5.66 1021 formula units of lithium nitrate per literHow many moles and numbers of ions of each type are present in the following aqueous solutions?
Convert ml to L and multiply by molarity to get answer


Multiply number of moles by 6.022 x 10^23 to get number of ion.





For example





0.0028L(2.41mol MgCl/1L) = .007mol MgCl





0.007( 6.022 x 10^23) = 4.22 x 10^23 ions

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