What is the probability of landing on 9 red or black numbers in a row on a roulette wheel?

not sure if the odds can be worked out or is it purley random?What is the probability of landing on 9 red or black numbers in a row on a roulette wheel?
its up to where the casino puts the magnet...no seriously, its 50-50 of getting red or black,the odds of landing on a specific number depends on how many numbers are involved and the times you will participate,probabilities are funWhat is the probability of landing on 9 red or black numbers in a row on a roulette wheel?
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the house will always win
Don't BET on it!!
If you let your stake ride you would get about 500-1
it will depend on the wheel, American wheels have two greens(0), British have just the one.
36 to one
I assume you mean either 9 consecutive red numbers OR 9 consecutive black numbers.





AMERICAN WHEELS have a zero and a double-zero so there are 38 possible results per spin.





When betting either red OR black, you have 18 favourable results.


So probability for each spin is 18/38


And the probability for 9 spins is (18/38) ^ 9


That's 18/38 raised to the ninth power


(i.e. 18/38 multiplied by itself nine times)


So the probability is:


198359290368 chances in 165216101262848


Expressed as a decimal that's 0.0012 (correct to 4 dec pl)


And the odds are approximately 832/1





EUROPEAN WHEELS have a zero but no double-zero so there are 37 possible results per spin.





When betting either red OR black, you have 18 favourable results.


So probability for each spin is 18/37


And the probability for 9 spins is (18/37) ^ 9


That's 18/37 raised to the ninth power


(i.e. 18/37 multiplied by itself nine times)


So the probability is:


198359290368 chances in 129961739795077


Expressed as a decimal that's 0.0015 (correct to 4 dec pl)


And the odds are approximately 654/1
I assume you mean red numbers in a row or black numbers in a row and not 9 numbers (black or red) in a row without encountering zero.





If so, the first colour is given (as it matters not whether it is red or black) so you do not have to bet on it; therefore you need to find the probability of following that first colour with 8 of the same. Assuming there is one zero, the answer is 18/37 to the power of 8, which is 0.0031733 or 317.75 to 1.





Alternatively, if on the first spin you merely have to avoid zero, then it is 36/37 x 0.0031733 or 0.0030525 = 326.6 to 1.